GradeMap

Grade 9 · Science · Unit 9 of 11

Circuits & Ohm's Law

Current, voltage and resistance

What your child practises

Circuit components and their jobs, current, potential difference and resistance with their symbols and SI units, calculating with V = I × R, and how current, voltage and resistance behave in series and parallel circuits.

Ontario Curriculum expectation: D2.3, D2.4, D2.5, D2.6 · DC circuit parts, electrical quantities and units, Ohm's law, and series and parallel circuits

Sample questions

A taste of this unit. In the app, questions change every time and get easier or harder to match your child.

  1. Question 1

    A thicker wire of the same material and length has…

    • less resistance
    • the same resistance
    • infinite resistance
    • more resistance
    Show answer

    less resistance

    Hint: A wider wire gives charge more room to flow.

  2. Question 2

    Two bulbs are in series. The current through the first is 2 A. What is the current through the second, in amperes?

    answer boxA

    Show answer

    2 A

    Hint: In a series circuit there is only one path, so the current is the same everywhere.

  3. Question 3

    In a parallel circuit, if one bulb burns out, the others…

    • get dimmer for good
    • stay lit
    • go out too
    • explode
    Show answer

    stay lit

    Hint: Each branch is its own path to the battery.

  4. Question 4

    A 20 V battery is connected across a 5 Ω resistor. What is the current, in amperes?

    answer boxA

    Show answer

    4 A

    Hint: I = V ÷ R = 20 ÷ 5 = 4 A.

  5. Question 5

    Two bulbs are connected in parallel across a 9 V battery. What is the potential difference across each bulb, in volts?

    answer boxV

    Show answer

    9 V

    Hint: Each branch of a parallel circuit has the same potential difference as the source.

  6. Question 6

    A circuit has a current of 2 A through a resistance of 6 Ω. What is the potential difference across it, in volts?

    answer boxV

    Show answer

    12 V

    Hint: V = I × R = 2 × 6 = 12 V.